ux+3uxy=0u(x,0)=sinx(dx/1)=(dy/3)y=3x+C(du/dx)=0u=αα=f(C)に代入するu=f(y-3x)u(x,0)=sinxより、f(0-3x)=sinx(-3x)=tとするとf(t)=sin(-t/3)t=(y-3x)のときf (y-3x)= sin(-(y-3x)/3)

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